998876 is only divisible (without remainder or fraction) by 2 which equals 499438. Not sure why there are two 5s in the question?
No. The only numbers that are divisible by 5 are the numbers that end with 5 or 0. In this case, it ends with 6, so 5 is NOT divisible by 998876. =)
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
Out of that list, only 2.
No. The only numbers that are divisible by 5 are the numbers that end with 5 or 0. In this case, it ends with 6, so 5 is NOT divisible by 998876. =)
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
It is divisible by 2, 5 and 10, but not 3 and 9.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.