One of the infinitely many integers divisible by 2, 3 and 5 is 3000.
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It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
30 is divisible by, and is the least common multiple of, 2, 3, and 5.
2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.
It is divisible by 2 and 5