No, it is instantaneous acceleration.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
It will measure acceleration in the direction towards or away from the origin.
The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.
Velocity is a vector; having direction. So, when changing direction constatly to have velocity a tangent can be drawn to the constantly changing path of the object having velocity.
The tangent at a point on the position-time graph represents the instantaneous velocity. 1. The tangent is the instantaneous slope. 2. Rather than "average" velocity, the slope gives you "instantaneous" velocity. The average of the instantaneous gives you average velocity.
The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.
As an object goes round in a circular path, then its velocity will along the tangent at that instant. But centripetal acceleration is normal to that tangent and so along the radius of curvature. As acceleration is perpendicular to the velocity, the direction aspect is ever changing and so the object goes round the circular path.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
The Instantaneous rate, or the rate of decomposition at a specific time, can be determined by finding the slope of a straight line tangent to the curver at that instant.
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
a=dv/dt=d/dt(dx/dt)=d^2x/dt^2Is the rate of a tangent to the slope of a graph signifying velocity versus time. It is a snapshot of acceleration at a precise moment in time based on the relative changes in velocity over time. It is the limit of acceleration for any given point within the displacement vector.Instantaneous acceleration is how fast a velocity is changing at a specific instant.
It is called instantaneous velocity and is the slope of the line tangent to the point on the position versus time graph. It also can be found by differentiating position with respect to time (i.e. dx/dt)Instantaneous Speed
It will measure acceleration in the direction towards or away from the origin.
The tangent (of a curve) is a vector that is tangent (perpendicular to the normal), i.e. the instantaneous velocity of the curve at a specific point. As such, the initial tangent is the initial velocity of the curve at the point where t=0. Stated in other terms, the tangent is the slope of the line at a point. This is expressed (in two dimensions, but applicable to higher dimensions), as the line that has x and y coordinates equal to the point of tangency, and slope equal to the limit of delta y over delta x as delta x (and delta y) approaches zero.
The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.
Allways...