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The slope of a line drawn tangent to a point on the curve of a position vs time graph describes what concept?
The slope of a line drawn tangent to a point on a position vs. time graph represents the instantaneous velocity of the object at that point. It describes how the position of the object is changing at that exact moment in time.
How would one determine Acceleration from a V-t Graph?
Acceleration can be determined from a velocity-time graph by calculating the slope of the line on the graph. The steeper the slope, the greater the acceleration. If the graph is curved, acceleration can be calculated by finding the tangent to the curve at a specific point.
What is the slope of the line tangent to the curve on a position-time graph at a specific time?
The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.
Is Average velocity the slope of the line tangent to the curve on a velocity time graph at a specific instant of time?
No, average velocity is the total displacement divided by the total time taken. The slope of the tangent to the curve on a velocity-time graph at a specific instant of time gives the instantaneous velocity at that moment, not the average velocity.
How do you find instantaneous velocity from position time graph?
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
What is a tangent line?
Tangent line is a graph. This graph is to gather data.
What do the asymptotes represent when you graph the tangent function?
When you graph a tangent function, the asymptotes represent x values 90 and 270.
A tangent-tangent angle intercepts two arcs that measure 149 and 211 What is the measure of the tangent-tangent angle?
31 degrees
A tangent-tangent angle intercepts two arcs that measure 135 and 225 What is the measure of the tangent-tangent angle?
45 degrees
Can you graph a negative tangent?
Hellz yea
A tangent-tangent angle intercepts two arcs that measure 164 and 196 What is the measure of the tangent-tangent angle?
196-164/2= 16
What does the slope of a tangent to the curve of a velocity-time graph measure?
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
A tangent-tangent angle intercepts two arcs that measure 124 and 236 What is the measure of the tangent-tangent angle?
236-124/2=56 degrees
Find the slope of a tangent line to the graph?
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
How do you locate rate of change on a graph?
Find the slope of the tangent to the graph at the point of interest.
Derivative as the Slope of a Tangent?
Yes, the derivative of an equation is the slope of a line tangent to the graph.
If A tangent tangent angle intercepts two arcs that measure 135 degrees and 225 degrees what is the measure of the tangent tangent angle?
The tangent-tangent angle is formed by two tangents drawn from a point outside a circle to points on the circle. To find the measure of the tangent-tangent angle, you take half the difference of the intercepted arcs. In this case, the arcs measure 135 degrees and 225 degrees. Therefore, the measure of the tangent-tangent angle is (\frac{1}{2} (225^\circ - 135^\circ) = \frac{1}{2} (90^\circ) = 45^\circ).
