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Q: Is The midpoint of a given line segment must lie on the given line segment?
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The midpoint of a given line segment must lie on the given line segment?

true


What must be true about a perpendicular bisector and the segment it bisects?

It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.


Can a segment bisect a line?

No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).


If a point is equidistant from the endpoints of a segment, then it must be the midpoint of the segment?

Yes


To construct a perpendicular bisector to a given line segment one must construct two?

Equilateral triangles


What must you do to construct the midpoint of a segment?

With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.


What must be true if a segment intersects another segment at more than one point?

That means that it is not a line segment.


How many planes must intersect to from a line?

A line segment can be defined as having two endpoints


Example of lines of symmetry in a nonagon?

A line of symmetry must go from one vertex to the midpoint of the opposite side.


To construct a perpendicular bisector to a given line segment one must construct two what?

Can't be sure what you're asking, but it would be two circles with equal radii longer that half the length of the segment, using the endpoints as the origins of the two circles.


A segment has exactly one end point?

A segment has two end points. If a line has one end point, then it must be called ray.


How is line m is the perpendicular bisector of XY. If line m intersects XY at point Z statements must be true?

The perpendicular bisector of the line XY will meet it at its midpoint at right angles.