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Yes, the midpoint of a given line segment must lie on that line segment. The midpoint is defined as the point that is equidistant from both endpoints of the segment, effectively dividing it into two equal parts. Therefore, by definition, the midpoint cannot exist outside of the line segment itself.
What else can I help you with?
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
If a point is equidistant from the endpoints of a segment then it must be the midpoint of the segment?
Yes, if a point is equidistant from the endpoints of a segment, it must be the midpoint of that segment. This is because the midpoint is defined as the point that divides the segment into two equal lengths, making it the only point that maintains equal distance to both endpoints. Therefore, being equidistant from both endpoints confirms that the point is indeed the midpoint.
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
What must be true if a segment intersects another segment at more than one point?
That means that it is not a line segment.
How many planes must intersect to from a line?
A line segment can be defined as having two endpoints
The midpoint of a given line segment must lie on the given line segment?
true
What must be true about a perpendicular bisector and the segment it bisects?
It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
If a point is equidistant from the endpoints of a segment, then it must be the midpoint of the segment?
Yes
To construct a perpendicular bisector to a given line segment one must construct two?
Equilateral triangles
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
What must be true if a segment intersects another segment at more than one point?
That means that it is not a line segment.
How many planes must intersect to from a line?
A line segment can be defined as having two endpoints
Example of lines of symmetry in a nonagon?
A line of symmetry must go from one vertex to the midpoint of the opposite side.
To construct a perpendicular bisector to a given line segment one must construct two what?
Can't be sure what you're asking, but it would be two circles with equal radii longer that half the length of the segment, using the endpoints as the origins of the two circles.
How is line m is the perpendicular bisector of XY. If line m intersects XY at point Z statements must be true?
The perpendicular bisector of the line XY will meet it at its midpoint at right angles.
A segment has exactly one end point?
A segment has two end points. If a line has one end point, then it must be called ray.
