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When constructing a perpendicular bisector why must the compass opening be greater than the length of the segment?
So that the arc is mid-way in perpendicular to the line segment
A rectangle has area 169 sq cm A straight line is to be drawn from one corner of the rectangle to the midpoint of one of the two more distant sides What is the minimum possible length of such a lin?
14.53 cm ======= the figure must be a square in order to have that line to a minimum value. then, if the area is 169, every side is 13 cm then, we use pytagoras: c2 = a2 + b2 a = 13 ; b = 13/2 solving for c c=14.53 Edit- I really do not have the time right now to work this problem out. However, I will say that the answer above is far from correct. First, the question does not ask from corner to corner, which would require the response above, rather it asks for the line to be drawn from one corner to the midpoint of one of the two more distant sides. Because it is the midpoint, you would have to create the area equation solve for a variable. Then create the Pythagorean theorem equation and find the derivative. Then plug in the value of the variable solved for in the area equation. Now you have to take this and find the critical points. After that plug them in to figure out which is the minimum value and you have your answer!
When an inequality is graphed would you shade the line?
The line must be solid if the inequality is strict (less than or greater than). It must be a dashed line if otherwise (less than or equal to, greater than or equal to).
Is finding the Riemann Sum of a curve just finding the midpoint rectangular approximation?
It could be. In addition to a Midpoint Rectangular Riemann Sum there is also a Left Rectangular Riemann Sum, a Right Rectangular Riemann Sum, and a Trapezoidal Riemann Sum. When you are asked to compute a Riemann Sum, you must choose from the above list depending on the specific question, your teacher's preferences, and/or your own preferences.
What is a function that forms a line graphed?
Any function of the form f(x) = ax + b, or any relation of the form Ax + By = C.This is the function that forms a line graphed. The slope of line can be taken out as C/A. * * * * * The above answer assumes that a line MUST be a straight line! Since the graph is a line, the domain must be an interval in the Real numbers. The interval may be finite, or infinite in one or both directions. In order that the graph does not have breaks in it the function must be continuous. Any such function will do.
Does the midpoint of a given line segment must lieon the given line segment?
Yes, the midpoint of a given line segment must lie on the line segment itself. The midpoint is defined as the point that divides the segment into two equal parts, which means it is located directly between the endpoints of the segment. Therefore, by definition, the midpoint is always a point on the line segment.
Is The midpoint of a given line segment must lie on the given line segment?
Yes, the midpoint of a given line segment must lie on that line segment. The midpoint is defined as the point that is equidistant from both endpoints of the segment, effectively dividing it into two equal parts. Therefore, by definition, the midpoint cannot exist outside of the line segment itself.
What must be true about a perpendicular bisector and the segment it bisects?
It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
If a point is equidistant from the endpoints of a segment, then it must be the midpoint of the segment?
Yes
If a point is equidistant from the endpoints of a segment then it must be the midpoint of the segment?
Yes, if a point is equidistant from the endpoints of a segment, it must be the midpoint of that segment. This is because the midpoint is defined as the point that divides the segment into two equal lengths, making it the only point that maintains equal distance to both endpoints. Therefore, being equidistant from both endpoints confirms that the point is indeed the midpoint.
To construct a perpendicular bisector to a given line segment one must construct two?
Equilateral triangles
If point A is not the midpoint of CT the CA can't equal AT?
If point A is not the midpoint of segment CT, it means that the distances from point C to point A (CA) and from point A to point T (AT) are not equal. The definition of a midpoint is that it divides a segment into two equal parts, so if A is not the midpoint, CA must be different from AT. Therefore, CA cannot equal AT if A is not the midpoint of CT.
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
What must be true if a segment intersects another segment at more than one point?
That means that it is not a line segment.
How many planes must intersect to from a line?
A line segment can be defined as having two endpoints
Example of lines of symmetry in a nonagon?
A line of symmetry must go from one vertex to the midpoint of the opposite side.
