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The midpoint of a given line segment must lie on the given line segment?
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∙ 13y ago
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Wiki User
∙ 13y ago
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When constructing a perpendicular bisector why must the compass opening be greater than the length of the segment?
So that the arc is mid-way in perpendicular to the line segment
A rectangle has area 169 sq cm A straight line is to be drawn from one corner of the rectangle to the midpoint of one of the two more distant sides What is the minimum possible length of such a lin?
14.53 cm ======= the figure must be a square in order to have that line to a minimum value. then, if the area is 169, every side is 13 cm then, we use pytagoras: c2 = a2 + b2 a = 13 ; b = 13/2 solving for c c=14.53 Edit- I really do not have the time right now to work this problem out. However, I will say that the answer above is far from correct. First, the question does not ask from corner to corner, which would require the response above, rather it asks for the line to be drawn from one corner to the midpoint of one of the two more distant sides. Because it is the midpoint, you would have to create the area equation solve for a variable. Then create the Pythagorean theorem equation and find the derivative. Then plug in the value of the variable solved for in the area equation. Now you have to take this and find the critical points. After that plug them in to figure out which is the minimum value and you have your answer!
When an inequality is graphed would you shade the line?
The line must be solid if the inequality is strict (less than or greater than). It must be a dashed line if otherwise (less than or equal to, greater than or equal to).
What two criteria must be true for a graph to be a proportional relationship?
It must be a straight line. It must pass through the origin.
Is finding the Riemann Sum of a curve just finding the midpoint rectangular approximation?
It could be. In addition to a Midpoint Rectangular Riemann Sum there is also a Left Rectangular Riemann Sum, a Right Rectangular Riemann Sum, and a Trapezoidal Riemann Sum. When you are asked to compute a Riemann Sum, you must choose from the above list depending on the specific question, your teacher's preferences, and/or your own preferences.
What must be true about a perpendicular bisector and the segment it bisects?
It bisects the line segment at midpoint at 90 degrees and its slope is the reciprocal of the line segment's slope plus or minus.
Can a segment bisect a line?
No. Since a line is infinite, it has no mid-point. A bisector must go through a midpoint so nothing can bisect a line (not even a segment).
If a point is equidistant from the endpoints of a segment, then it must be the midpoint of the segment?
Yes
To construct a perpendicular bisector to a given line segment one must construct two?
Equilateral triangles
What must you do to construct the midpoint of a segment?
With a straight-edge and a compass:Swing arcs from each end of the segment with the compass (without changing the settings)Connect the intersections of these arcs.The resultant is a perpendicular bisector of the segment.
What must be true if a segment intersects another segment at more than one point?
That means that it is not a line segment.
How many planes must intersect to from a line?
A line segment can be defined as having two endpoints
Example of lines of symmetry in a nonagon?
A line of symmetry must go from one vertex to the midpoint of the opposite side.
To construct a perpendicular bisector to a given line segment one must construct two what?
Can't be sure what you're asking, but it would be two circles with equal radii longer that half the length of the segment, using the endpoints as the origins of the two circles.
How is line m is the perpendicular bisector of XY. If line m intersects XY at point Z statements must be true?
The perpendicular bisector of the line XY will meet it at its midpoint at right angles.
A segment has exactly one end point?
A segment has two end points. If a line has one end point, then it must be called ray.
How is that any line intersecting the interior of a given circle is a secant of that circle?
Any line that enters a circle (and is not a tangent) must cross its boundary twice; once to enter, once to exit. Since a secant is a line segment that joins two different points on a curve, such a line as above is a secant.
