The expressions does not have rational factors but it does have real factors, so it is not prime. Furthermore, the value of the expression will be prime for some values of x and not for others.
12
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
the answer is (3x-2)(9x squared+6x+4)
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
(3x - y+ 2)(3x + y + 2)
12
(3x + 3y)(x + y) = 3(x + y)2
x^2+2x^2=3x^2
(3x-2)(x-2)
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared
It is a quadratic expression and can be factored into: (3x+1)(x+2)
(x - 4)(3x - 2)
(3x - 2)(x + 8)
x3+3x2+3x+2 divided by x+2 equals x2+x+1
(x + 2)(x + 1)