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Q: Is X squared plus 3x -2 prime?

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x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)

(3x - y+ 2)(3x + y + 2)

12

(3x + 3y)(x + y) = 3(x + y)2

It is a quadratic expression and can be factored into: (3x+1)(x+2)

x3+3x2+3x+2 divided by x+2 equals x2+x+1

x^2+2x^2=3x^2

(3x - 1)(x + 2)

(3x-2)(x-2)

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared

This is (3x +2)2 so if x is an integer/3, this expression is the square of an integer so cannot be prime. Anything else, and it's not even an integer.

(x - 4)(3x - 2)

(3x - 2)(x + 8)

(x + 2)(x + 1)

(x + 2)(x + 1)

-1

3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)

3x2+x-2 = (3x-2)(x+1) when factored

(x^2 - 3x + 5)(x^2 + 3x + 5)

3x 2 + 2x - 5 = (x - 1)(3x + 5).

The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].

3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)

(x + 3)(3x - 2)

Yes, it is 2

3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)