Study guides

☆☆

Q: How do you factor the expression 27x cubed plus 8?

Write your answer...

Submit

Still have questions?

Continue Learning about Calculus

9x(x2+3x-10)

Your question is ambiguous. (3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6 or, if you meant 3x^3 times 3x^3 = 9x^6

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]

y will be multiplied by 27. Remember, whatever you do to one side of an equation, you must do to the other. In this case, the relationship between x and y would be expressed as y = x^3 To triple x would look like y = (3x)^3 ...b/c you're tripling the value x alone, not the entire term x^3 y = 27x^3 ...after distributing the exponent (3^3 = 27) In order to set both sides of the equation equal, y must be multiplied by 27... 27y = 27x^3 TADA!

Related questions

9x(x2+3x-10)

(8x + 9)(3x^2 - 1)

3x2 + 27x +60

I also need to know the answer to this problem. Can anyone answer it?

(2 - 3x)(9x^2 + 6x + 4)

19

9x

27x/9x = 3x

Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)

(2x - 3)(x - 12)

27x + 23 or 27x - 23

In order to factor the sum of the cubes, we need to use this form a³ + b³ = (a + b)(a² - ab + b²). Let a³ = 27x³ and b³ = 343y³. Then, a = 3x and b = 7y. Perform substitution of these terms for the form, and we obtain: 27x3 + 343y3 = (3x + 7y)(9x2 - 21xy + 49y2)

People also asked