Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
If you mean: (x+3) squared = (x+2) squared +11 Then the value of x works out as 3
2x2 + 28xy + 98y2 = 2(x + 7)2.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
(a + x^2)(b + y^2)
x^2+x^2=2x^2
(x+y)2
Add the x's squared together to get 2x^2+x. You cannot add anymore so the answer is 2x^2+x
8 + X SQUARED
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
(x + 2)(x + 1)
(x + 2)(x + 1)
(x+2)(x+2) or (x+2)^2
2x2 + (5x-4x)2 + (x-x)2 = 2x2 + x2 + 02 = 2x2 + x2 = 3x2
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
x^2 + x -x^2 +1 =x+1