Assuming that the perimeter of the regular octagon is 32 inches, and since it has 8 sides, then the length of one side of the figure is 32/8 or 4 inches.
An octagon is an eight-sided figure. If a regular octagon has a perimeter of 24 inches, then each side will be 24 / 8 = 3 inches.
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
"Regular" = all sides are the same length"Octagon" = it has 8 sidesEach side = 25 cmPerimeter = 8 x 25 cm = 200 cm
7 feet
If the perimeter of the hexagon is 24 cm and it is regular, then each side has the same length, namely 24/6 or 4. Now that is also the length of each side of the octagon since they share a common side so its perimeter is 8x4=32 cm.
An octagon is an eight-sided figure. If a regular octagon has a perimeter of 24 inches, then each side will be 24 / 8 = 3 inches.
112 inches, that is if all the sides are the same length .I think.
A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches
8 sides each 9 inches: 6 feet
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
An octagon is a polygon with 8 sides. To find the diameter of a regular octagon when each side is 18 inches in length, you can use the formula: Diameter = Side length × √(2 + √2) Plugging in the given side length (18 inches): Diameter = 18 × √(2 + √2) ≈ 56.97 inches So, the diameter of the octagon is approximately 56.97 inches.
' 8a ' is.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
The length of one side of an octagon, if the perimeter is 6 feet, is 9 inches.
8*length of side.
Any length greater than zero.
80ft