The perimeter would be 64 - since 8 x 8 = 64 !
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' 8a ' is.
64 cm
Multiply the length of one side (7 cm) by the number of side (8) to see that the perimeter is 56 cm. This works because a regular octagon has 8 sides of equal length..
By using the definition of "perimeter": you need to add the lengths of all eight sides. If it is a REGULAR octagon, you multiply the length of any side by 8, since all sides have the same length.
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm
' 8a ' is.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.
If it's a regular octagon, the perimeter is 8 times the length of one side.
The perimeter is 72.
8*length of side.
80ft
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
12ft
64 cm
To find the length of each side of a regular octagon with a perimeter of 56, we divide the perimeter by the number of sides. Since an octagon has 8 sides, we divide 56 by 8 to get 7. Therefore, each side of the regular octagon is 7 units long.
208/8 = 26mm
Assuming that the perimeter of the regular octagon is 32 inches, and since it has 8 sides, then the length of one side of the figure is 32/8 or 4 inches.