Yes, it is.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Electric flux.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Because if you place a small object with a small electric charge in the field and release it, there's a definite direction in which it will move under the influence of the field. The direction in which a positive test-charge tries to move is defined as the direction of the electric field at that point. Since it has both a magnitude and a direction, it has all the qualifications to be recognized as a vector, and to be granted all the rights and privileges attendant thereto.
Electric Field Intensity also simply referred to as the Electric Field is a vector quantity with the units (V/m) (Volts per meter) Symbol: E (Boldface to represent a vector)Electric Potential is a scalar quantity with units V (Volts). Also sometimes referred to as Voltage when dealing with the difference between two points. Symbol: V (non-bolded to represent a scalar)The relationship between the two is:The Electric Field Intensity E is equal to the negative of the gradient of V.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
Scaler. The electric field is its vector counterpart.
I think light could not be recoginzed as a vector. However, I think the light intensity could be devided into the x-y axises.
Zero Dipole would set itself such that dipole moment vector is along the electric field vector
Electric flux.
Scaler. Its vector counterpart is the electric field.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.