Yes, it is.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Electric flux.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
Yes, electric field intensity is a vector quantity because it has both magnitude and direction. The direction of the electric field intensity indicates the direction of the force that a positive test charge would experience if placed in that field.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
The electric field intensity is formed by the presence of electric charges. It is a vector quantity that represents the force experienced by a positive test charge per unit charge at a given point in space. The magnitude and direction of the electric field intensity depend on the distribution of charges in the vicinity.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Electric Field Intensity also simply referred to as the Electric Field is a vector quantity with the units (V/m) (Volts per meter) Symbol: E (Boldface to represent a vector)Electric Potential is a scalar quantity with units V (Volts). Also sometimes referred to as Voltage when dealing with the difference between two points. Symbol: V (non-bolded to represent a scalar)The relationship between the two is:The Electric Field Intensity E is equal to the negative of the gradient of V.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Electric field intensity is related to electric potential by the equation E = -∇V, where E is the electric field intensity and V is the electric potential. This means that the electric field points in the direction of steepest decrease of the electric potential. In other words, the electric field intensity is the negative gradient of the electric potential.
Because if you place a small object with a small electric charge in the field and release it, there's a definite direction in which it will move under the influence of the field. The direction in which a positive test-charge tries to move is defined as the direction of the electric field at that point. Since it has both a magnitude and a direction, it has all the qualifications to be recognized as a vector, and to be granted all the rights and privileges attendant thereto.
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
The intensity of an electric field is determined by the amount of charge creating the field and the distance from the charge. The closer you are to the charge, the stronger the electric field will be.
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
Scaler. The electric field is its vector counterpart.