No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
Electric flux.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
Yes, electric field intensity is a vector quantity because it has both magnitude and direction. The direction of the electric field intensity indicates the direction of the force that a positive test charge would experience if placed in that field.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
The electric field intensity is formed by the presence of electric charges. It is a vector quantity that represents the force experienced by a positive test charge per unit charge at a given point in space. The magnitude and direction of the electric field intensity depend on the distribution of charges in the vicinity.
Electric field intensity (E) measures the force experienced by a charged object in an electric field, while electric potential (V) represents the potential energy per unit charge at a specific point in the field. The unit of electric field intensity is volts per meter (V/m), and the unit of electric potential is volts (V).
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Electric field intensity is related to electric potential by the equation E = -∇V, where E is the electric field intensity and V is the electric potential. This means that the electric field points in the direction of steepest decrease of the electric potential. In other words, the electric field intensity is the negative gradient of the electric potential.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.
An electric field is considered a vector quantity because it has both magnitude and direction. The direction of the electric field at any point indicates the direction that a positive test charge would experience a force if placed at that point.
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
The electric strength force, or electric field intensity, measures the force exerted on a unit positive charge placed in an electric field. It is a vector quantity that describes the direction and magnitude of the force experienced by a charge in the presence of an electric field. It is measured in units of newtons per coulomb (N/C).
Scaler. The electric field is its vector counterpart.