Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation.
0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
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Actually electric field is the region around an
electric charge in which it exerts force on other charges. Being a region in space it is scalar quantity.
But if we talk about electric field intensity it is the force which a unit charge feels in the electric field of another charged particle. Since Force is vector quantity, and a vector divided by a scalar remains a vector, therefore it is a vector quantity. Given by,
E=F/q
where E and F are vectors electric field intensity and force respectively. and q is charge.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Vector.
A scalar times a vector is a vector.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.