Yes, it's true. 3 is one of the factors of 6, so any number that has six as a factor also has 3 as a factor.
Every sixth number from 1,002 to 9,996 is divisible by 3 and 6. There are 1,500 of them.
Since 3 is a factor of 6, any number divisible by 6 is also divisible by 3. But since 2 is also a factor of 6, then any number divisible by 6 must also be divisible by 2. This means that any number divisible by 6 is an even number. So if a number is odd and it is divisible by 3, then it is not divisible by 6. For example, 12 is divisible by 3, but since it is even, it is also divisible by 6. But 15 is divisible by 3, and it is odd, so it is not divisible by 6.
As 6 is divisible by 3, ANY dumber divisible by 6 is also therefore divisible by 3. Any number divisible by 3 is ALSO a multiple of 3.
If a number is divisible by 2 and 3, it is divisible by 6.
if the number is a 2 or more diget number, you add up all of the numbers in the number and when you have the sum, if the sum is divisible by 3 , the whole number is divisible by three EX. 123=6, 6 is divisible by 3 so 123 is divisible by three 447=15 is divisible by 3 so 447 is divisible by 3 989=26 is *NOT* divisible by 3 so 989 is not divisible by three this truly does work for every single number
Every sixth number from 1,002 to 9,996 is divisible by 3 and 6. There are 1,500 of them.
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
No, 9 is divisible by 3 and 9, but not six 3 x 9 = 27, also not divisible by 6
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
Since 3 is a factor of 6, any number divisible by 6 is also divisible by 3. But since 2 is also a factor of 6, then any number divisible by 6 must also be divisible by 2. This means that any number divisible by 6 is an even number. So if a number is odd and it is divisible by 3, then it is not divisible by 6. For example, 12 is divisible by 3, but since it is even, it is also divisible by 6. But 15 is divisible by 3, and it is odd, so it is not divisible by 6.
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
As 6 is divisible by 3, ANY dumber divisible by 6 is also therefore divisible by 3. Any number divisible by 3 is ALSO a multiple of 3.
if a number is divisible by 2 and 3 then its divisible by 6
If a number is divisible by 2 and 3, it is divisible by 6.
These numbers are not evenly divisible by 6: Any number smaller than 6. Any odd number (not divisible by 2). Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Not always as for example 81 is divisible by 3 but not by 6
If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.