yeah
3 9 15 21 27 and so on
(every other multiple of three)
But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.
Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.
So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
No. Only even numbers are divisible by 2.
15
If a number is divisible by both three and four, it's divisible by twelve.
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
Well, isn't that just a happy little math problem! Let's see here... numbers that are divisible by 3 but not by 6 would be 12, 15, 18, 21, 24, 27, 33, 39, 42, 45, 48, 51, 57, 63, 69, 72, 75, 78, 81, and 87. Remember, math is just like painting - it's all about finding the right colors and shapes that fit together beautifully!
As 6 is divisible by 3, ANY dumber divisible by 6 is also therefore divisible by 3. Any number divisible by 3 is ALSO a multiple of 3.
if a number is divisible by 2 and 3 then its divisible by 6
If a number is divisible by 2 and 3, it is divisible by 6.
Not always as for example 81 is divisible by 3 but not by 6
If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
It is not divisible by 6. Note:If a number id divisible by 6 then it must be divisible by both 2 and 3.The above number is not divisible by 2 and 3 either.
Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
It is divisible by 6