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yeah

3 9 15 21 27 and so on

(every other multiple of three)

But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.

Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.

So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.

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8y ago
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Q: Is there a number divisible by 6. But not 3?
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