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Q: Is it true that 305 can be divisible by 2 and 5?

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To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.

305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.

610 is divisible by these factors: 1, 2, 5, 10, 61, 122, 305, 610.

305 is divisible by any of its factors, which are 1, 5, 61, and 305.

5, yes. 2, 3, 6, 9, 10, no.

Yes to 5. No to 3.

1, 2, 5, 10, 25, 50, 61, 122, 305, 610, 1525, 3050.

Because it is divisible by 5, a number which is not 1 nor 305 itself.

-- Neither 2 nor 5 is divisible by 18. -- 18 is divisible by 2, but not by 5.

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