Yes to 5. No to 3.
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
a number that is divisible by 3 and 5 but not by 4= 15
It really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htmIt really isn't worthwhile to find complicated divisibility rules for large numbers like 305 - because if there really is a divisibility rule, it will certainly be more complicated than just doing the division.Anyway, 305 = 5 x 61, so if a number is divisible by 305, it must be divisible by 5, and by 61. Divisibility by 5 is fairly simple; a number is divisible by 5 if it ends with 0 or 5. For divisibility by 61, see the following link; it looks fairly complicated.http://www.primepuzzles.net/puzzles/puzz_101.htm
No, 3 is not divisible by 555. In order for a number to be divisible by another number, the remainder when dividing the first number by the second number must be zero. In this case, when dividing 3 by 555, the remainder is 3, indicating that 3 is not divisible by 555.
Well, honey, let's break it down. 305 is not divisible by 2, 3, 5, or 6 because it's an odd number and doesn't meet the divisibility rules for those numbers. As for 9 and 10, nope, it doesn't work for them either because the sum of the digits of 305 isn't divisible by 9, and it doesn't end in 0 for 10. So, in short, 305 is a lone wolf that can't be divided by any of those numbers.
305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.
Only 315. To be divisible by 3 numbers have to add to a number divisible by 3 (3+1+5 =9). To be disable by 5, number has to end in a 5 or 0
5All Factors of 305:1, 5, 61, 305
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
A number that is divisible by 15 is divisible both by 5 and 3 A number is divisible by 5 if it ends with 0 or 5 A number is divisible by 3 if the sum of its digits is divisible by 3 e.g. 4035 is divisible by 15 as it ends with a 5 and 4+0+3+5=12 which is divisible by 3
Since '305' is an ODD Number, it is NOT divisible by '2' However, since it ends in '5' it is divisible by '5'. NB EVEN numvers ends in 0,2,4,6,8 ODD Numbers end in 1,3,5,7,9 since 305; ends in ;5; it is an ODD Numbers. Here are some 'tricks to remember. #1 ALL Even numbers are divisible by '2'. #2 All numbers ending in '--5' or '--0' are divisible by '5'. #3 All numbers ending in '---0' are divisible by '2;, & 10.; #4 If the sum of the digits of numbers add to '9', then it is divisible by '9'. e.g. 144 ; 1 + 4 + 4 = 9 . So ;144; is divisible by '9' #5 This only leaves '3' and '7' were you have to fully test the divisibility of a numbers. #6 To test for '11' . Then a number such as 132 will divide by '11' because if the sum of the two end number is equal to the middle number, then it will divide by ;11; e.g. ''1' & '2' added make '3' , which is the middle number of '132' . 154 is another number as is 297.
Because it is divisible by 5, a number which is not 1 nor 305 itself.
a number that is divisible by 3 and 5 but not by 4= 15
1, 3, 5, 15, 61, 183, 305, 915.
15 is divisible by 3 and 5.
305 is divisible by any of its factors, which are 1, 5, 61, and 305.