No, it is not true that a segment's bisector will always be congruent to the segment itself. A segment bisector is a line, ray, or segment that divides the original segment into two equal parts, but the bisector itself does not have to be equal in length to the original segment. For example, if you have a segment of length 10 units, its bisector will simply divide it into two segments of 5 units each, but the bisector itself can be of any length and orientation.
By definition, a segment bisector always created two congruent segments.
A segment has exactly one bisector. This bisector is a line (or line segment) that divides the original segment into two equal parts and is perpendicular to it. No matter the length of the segment, the unique bisector will always pass through the midpoint of the segment.
A perpendicular bisector intersects a line segment at a right angle, forming two 90-degree angles with the segment. This means that the angle between the bisector and the line segment is always a right angle, indicating that the bisector divides the segment into two equal parts.
A circle itself does not form a perpendicular bisector because a perpendicular bisector is a line that divides a segment into two equal parts at a right angle, typically associated with straight segments. However, the concept of a perpendicular bisector can be applied to chords within a circle. The perpendicular bisector of a chord will always pass through the center of the circle.
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
By definition, a segment bisector always created two congruent segments.
It Separates BC (Line on top) into two congruent line segments.
A segment has exactly one bisector. This bisector is a line (or line segment) that divides the original segment into two equal parts and is perpendicular to it. No matter the length of the segment, the unique bisector will always pass through the midpoint of the segment.
A perpendicular bisector intersects a line segment at a right angle, forming two 90-degree angles with the segment. This means that the angle between the bisector and the line segment is always a right angle, indicating that the bisector divides the segment into two equal parts.
A circle itself does not form a perpendicular bisector because a perpendicular bisector is a line that divides a segment into two equal parts at a right angle, typically associated with straight segments. However, the concept of a perpendicular bisector can be applied to chords within a circle. The perpendicular bisector of a chord will always pass through the center of the circle.
Not sure what an "irie" is. But a bisector does not need to be perpendicular.
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If by "equal" you mean "equal in length", yes, that is the same as "congruent".
Not always because the diagonals of a rectangle bisect each other but they are not perpendicular to each other.
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Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.