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A multiple of 4 can be written as 4j, where j is any integer. So for example, letting j = 1, 2, 3, 4, 5, etc., leads to values for 4j of 4, 8, 12, 16, 20, etc; all being multiples of 4.

So if we have two multiples of 4, say 4m and 4n (with m and n both being integers), then their sum will be 4m + 4n, which can also be written as 4(m + n) by factoring out the 4. Since m and n are integers, (m + n) will also be an integer, so the sum of 4(m + n) is a multiple of 4.

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14y ago

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