No.
There is no agreed definition for an outlier: there are several options. However, with the given set of numbers, none of them are likely to be outliers.
yes 14 and 4 are
I'm not seeing one. Outliers are usually way off from the rest of the group (ex 150)
It is an extreme in a group of numbers.They are much smaller or bigger than the group of numbers. For example, in: 5 6 8 7 5 4 15 15 is obviously an outlier as it is very much higher than the rest of the numbers..
The median of the given set of numbers {7, 6, 8, 9, 7} is 7. To calculate the median of a set of numbers, we first need to arrange them in ascending order. The sorted set of numbers is {6, 7, 7, 8, 9}. Since the number of terms in the set is odd (5), the median is the middle term. In this case, the middle term is 7
For a standard set, the tiebreak starts at 6-6 and a set tiebreak is played (first to 7, win by 2). In an 8-game pro-set generally a tiebreak is played at 8-8 and it is a super tiebreak (first to 10, win by 2).
the mode is 8 more than the outlier.
6 6 5 5 6 6 -4 -4 5 -5 6 -6 -7 6 6 6 5 5 6 6 -4 -4 -8 7 -8 8 -6 -8 6 8 8 -8 7 7 -7 -7 7 -8 -7 -6 6 7 7 7 -6 -6 7 7 6 6 6 -6 7 6 -8 7
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
5, 6, 7, 8, 14
8