No.
There is no agreed definition for an outlier: there are several options. However, with the given set of numbers, none of them are likely to be outliers.
yes 14 and 4 are
In the set of data 4, 5, 6, 6, 6, 7, 7, 8, 9, 10, 100, the number 100 is much greater than the rest, so it is an outlier. An outlier is a value that significantly deviates from the other observations in a dataset, potentially skewing the analysis or interpretation of the data. In this case, 100 stands out as an extreme value compared to the other numbers.
I'm not seeing one. Outliers are usually way off from the rest of the group (ex 150)
It is an extreme in a group of numbers.They are much smaller or bigger than the group of numbers. For example, in: 5 6 8 7 5 4 15 15 is obviously an outlier as it is very much higher than the rest of the numbers..
The median of the given set of numbers {7, 6, 8, 9, 7} is 7. To calculate the median of a set of numbers, we first need to arrange them in ascending order. The sorted set of numbers is {6, 7, 7, 8, 9}. Since the number of terms in the set is odd (5), the median is the middle term. In this case, the middle term is 7
For a standard set, the tiebreak starts at 6-6 and a set tiebreak is played (first to 7, win by 2). In an 8-game pro-set generally a tiebreak is played at 8-8 and it is a super tiebreak (first to 10, win by 2).
the mode is 8 more than the outlier.
6 6 5 5 6 6 -4 -4 5 -5 6 -6 -7 6 6 6 5 5 6 6 -4 -4 -8 7 -8 8 -6 -8 6 8 8 -8 7 7 -7 -7 7 -8 -7 -6 6 7 7 7 -6 -6 7 7 6 6 6 -6 7 6 -8 7
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
5, 6, 7, 8, 14