what is the median of these numbers 5 6 6 7 8 9 9 0 2 3 5 6 8 8 8 8 0 1 2 3 5 5 6 7 7 8 0 2 4 5 7 8
The median is 6.
There are several possible interpretations of the question:(6/7) / (8/21)6 / [7/(8/21)]6 / [(7/8)/21]et ceteraAssuming it is the first of these, (6/7) / (8/21) = (6/7) * (21/8) = (3/7) * (21/4)= (3/1) * (3/4) = 9/4 or 21/4
In the dataset {8, 0, 7, 7, 9, 12, 3, 7, 4, 6, 7, 8, 9, 6, 4} the 8 appears twice. → The frequency of the 8 is 2.
4.5
No.
yes 14 and 4 are
I'm not seeing one. Outliers are usually way off from the rest of the group (ex 150)
It is an extreme in a group of numbers.They are much smaller or bigger than the group of numbers. For example, in: 5 6 8 7 5 4 15 15 is obviously an outlier as it is very much higher than the rest of the numbers..
the mode is 8 more than the outlier.
7
6 6 5 5 6 6 -4 -4 5 -5 6 -6 -7 6 6 6 5 5 6 6 -4 -4 -8 7 -8 8 -6 -8 6 8 8 -8 7 7 -7 -7 7 -8 -7 -6 6 7 7 7 -6 -6 7 7 6 6 6 -6 7 6 -8 7
An outlier can make the range go up.Example:say you have the numbers. 2,5,4,1,7,and 18.in order from least to greatest: 1,2,4,5,7,18range is the greatest number - the littlest number.so in this case it is 18-1 which equals 17say if there was no outlier and the highest number was 7it would be 7-1 which is 6 and it makes the outlier smaller....
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
6 6 -6 6 7 -7 6 6 -6 6 -8 7 6 6 9 8 7 -7 -6 -9 -9 8 7 -8 7
It states that (ab)c = a(bc).
5 6 -8 7 6 -5 5 5 5 -5 6 -6 6 5 6 -8 7 6 -5 6 6 6 -6 -7 7 7 -8 6 6 -7 -6 6 5 6 7 -6 7 -8 7 -7 6 5 6 -8 7 6 -5 6 6 6 -6 -7 7