I'm not seeing one. Outliers are usually way off from the rest of the group (ex 150)
yes 14 and 4 are
It is an extreme in a group of numbers.They are much smaller or bigger than the group of numbers. For example, in: 5 6 8 7 5 4 15 15 is obviously an outlier as it is very much higher than the rest of the numbers..
No.
4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4 7 -7 -6 6 -7 6 -6 -5 6 7 -7 -6 6 -7 7 -7 -6 6 -7 6 -6 -5 6 5 -5 5 4 4 4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4
There is no agreed definition for an outlier: there are several options. However, with the given set of numbers, none of them are likely to be outliers.
G:--------------: d:--------------: a:-4-5-6-7------: e:---------7-0--: g:--------------------5-4----------------------------: d:----------4-5----4-5------5-9-8~-----7-5-----------: a:-4-5-6-7------6-7-------7--------------7-5-7-------:- e:---------------------------------------------------: g:---------------------5-4-----7-5--: d:---------4-5-----4-5-------5------: a:-4-5-6-7-----6-7---------7--------: e:----------------------------------: g:---------9-7--------------------------------: d:--------------9-7-5---8-7-8-7-8-7-5---------: a:-4-5-6-7------------7----------------7-5-7--: e:--------------------------------------------:
6 6 5 5 6 6 -4 -4 5 -5 6 -6 -7 6 6 6 5 5 6 6 -4 -4 -8 7 -8 8 -6 -8 6 8 8 -8 7 7 -7 -7 7 -8 -7 -6 6 7 7 7 -6 -6 7 7 6 6 6 -6 7 6 -8 7
4/5*6/7 = (4*6)/(5*7) = 24/35
7 + 5 + 4 + 5 + 3 + 4 + 6 + 5 + 4 + 5 + 6 + 4 + 7 = 65
7!/2! = 7*6*5*4*3 = 25207!/2! = 7*6*5*4*3 = 25207!/2! = 7*6*5*4*3 = 25207!/2! = 7*6*5*4*3 = 2520
5
4 x 6(7+5)*(6-4) = 24