Yes, 2x is 2 times x.
2x2- 2x = 2x*(x - 1)
x2 - 2x = x(x-2)
4
x(x + 2)
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
2x(x - 4)(x + 4)
2x(x^2+x-6)
-4
2x2 + 6xy = 2x (x + 3y)
The factor is 2x^2(x^2-9)
x(x - 2)
Factor out -2x since that is the GCD of the terms, so we obtain: -2x(x² + 5x + 6) By decomposition, we have: -2x(x² + 3x + 2x + 6) Factor-by-grouping, we obtain: -2x(x(x + 3) + 2(x + 3)) = -2x(x + 2)(x + 3) [Collect the terms and group the binomials]