0
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-4
Hailee Hills ∙
(2x+3)(x-2)
2(x + 3)(x + 1)
x(x - 2)
(x + 2)(x - 4)
4
2(x - 7)(x - 1)
2x(x^2+x-6)
(2x + 3)(x - 2)
(2x - 3)(x + 2)
(x - 2)(2x + 3)
8
(x - 2)(2x - 3)
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
x2 - 2x = x(x-2)
No.