{3x +y =1 {x+y= -3
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
Point-Slope formula: y - y1=m(x - x1) y = 2/3x + 1
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
81
If you mean: 3x-y = 1 then it is a straight line equation
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
3x-4y=40 (x=0) 3(0)-4y=40 -4y=40 y=40/-4 y=-10 x1 , y1 (13 , -10) (4y=0) 3x-4(0)=40 3x=40 x=40/3 x=13.33 or 13
This is not possible to answer without knowing where the equality sign is meant to be.
We can use the point slope form.Y - Y1 = m(X - X1)----------------------Y - (- 6) = - 3(X - 4)Y + 6 = - 3X + 12Y = - 3X + 6============equation of the line
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
Point-Slope formula: y - y1=m(x - x1) y = 2/3x + 1
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
- 3x - Xsame as- 3x + (- X)= - 4X=====
The distance between (x, y1) and (x, y2) is abs(y1 - y2) or |y1 - y2|.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1