It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
Point-Slope formula: y - y1=m(x - x1) y = 2/3x + 1
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
y - y1 = m(x - x1), where m is the slope of the line, and (x1, y1) is a point on the line.
81
If you mean: 3x-y = 1 then it is a straight line equation
3x-4y=40 (x=0) 3(0)-4y=40 -4y=40 y=40/-4 y=-10 x1 , y1 (13 , -10) (4y=0) 3x-4(0)=40 3x=40 x=40/3 x=13.33 or 13
It is not possible to give a sensible answer because the operator between y1 and 9x is not visible.
This is not possible to answer without knowing where the equality sign is meant to be.
We can use the point slope form.Y - Y1 = m(X - X1)----------------------Y - (- 6) = - 3(X - 4)Y + 6 = - 3X + 12Y = - 3X + 6============equation of the line
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
Point-Slope formula: y - y1=m(x - x1) y = 2/3x + 1
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
- 3x - Xsame as- 3x + (- X)= - 4X=====
The distance between (x, y1) and (x, y2) is abs(y1 - y2) or |y1 - y2|.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1