y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
The algebraic expression of: -x-1y has the same value as -x-y
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1
y-2y8y-6 1y-2y8y-6 1y-6y-6 5y-6 1y
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When you have a variable by itself either it be x or y there is always an invisible place holder before it. So a normal "y" would be "1y". So when you put 1y + 1y you get 2y.
Y=2xx+y=3x+(2x)=33x=3x=1y=2x y=2*1y=2
The algebraic expression of: -x-1y has the same value as -x-y
6-1y+(5y-6y) = 6-y+(-1y) = 6
-2y+y = -y
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
6x -1y = 9 y-intercept = -9
Here's how it is:2y + 10 = 5y - 4ySolution:2y + 10 = 1y (subtract 5y and 4y)10 = 1y - 2y10 = -1y-1(10 = -1y)y = -10
1
y = 2x + 1 1. Make a table: x = -2; y = -3y = 2x + 1y = 2(-2) + 1 = -4 + 1 = -3 x = -1; y = -1y = 2x + 1y = 2(-1) + 1 = -2 + 1 = -1x = 0; y = 1y = 2x + 1y = 2(0) + 1 = 0 + 1 = 1 x = 1; y = 3y = 2x + 1y = 2(1) + 1 = 2 + 1 = 3 x = 2; y = 5y = 2x + 1y = 2(2) + 1 = 4 + 1 = 5 2. Plug the points (-2, -3), (-1, -1), (0, 1), (1, 3), and (2, 5) in a xy-coordinate system. 3. Draw a line which passes through those points. Thus, the line drawn is the graph of the function y = 2x + 1