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7

k = f(n) = 7n

35 + 2k = 9k subtract 2k from each side 35 + 2k - 2k = 9k - 2k 35 = 7k divide both sides integers by 7 35/7 = (7/7)k 5 = k check in original equation 35 + 2(5) = 9(5) 35 + 10 = 45 45 = 45 checks out

Since r varies directly with s, we have r = ks (replace k with 5 and s with 7) r = (5)(7) r = 35

k would equal 8. you add the powers on one side of the equation together so you should end up with 7 to the power of 11 then you minus 7 to the power 3 from the opposite side of the equation leaving you with 7 to the power 8 equals 7 to the power k. you can then see that k is the equivalent of 8.

The value of k is 0

4k-7 = 7 4k = 14 k = 3.5 or k = 7/2

35.

k=-7

3/7 of 35 is 15.

79 + k = 84 84 - 79 = k k = 5

7. Calculating 1/5 of a number is the same is just dividing by 5, so in this case you would need to divide 35 by 5, which would give you an answer of 7.It is: 1/5 of 35 = 7

==> 3k+14=k ==>3k-k=-14 ==>2k=-14 ==>k=-7 ans...

racist

Take 3k from both sides to get k-3 equals 4, so k is 7

k * 4 = 48 k = 48/4 k = 12 so 12 * 4 = 48

2+2+7=11 K?

k + 6k - 13 = 177k = 30k = 30/7k = 4.2857

"K" could be located at 7.

It simplifies to 7k = 49 which gives k = 7.

4k = 28 Therefore, 28/4 = 7 k = 7

k=.81 17 times over then, 82

6 multiples of 7 are: 14, 21, 28, 35, 42, and 49

x*y = k where k is a constant.When x = 9, y = 7 so k = 9*7 = 63 When x = 21, 21*y = 63 so y = 3.

xy = K so K = 21