2k + 3 = 11(- 3 from both sides)2k = 8(divide both sides by 2)k = 4
Let even be of the form 2k and odd be of the form 2k+1. Then odd * even becomes 2k*2k+1, or 4k^2 +2k. This can be written as 2(k^2 + k), which is of the form 2k. Therefore, odd X even equals even.
-4. -3k+10=k+2.... First we have to move the K to one side -3k+10=k+2 __________ This will reduce -3k to -2k and k+2 to just 2 K -2k+10=2 Now we have to subtract 10 to both sides as to get k alone. -2k+10=2 ________ Now we should have -2k on one side and 2-10 on the other. -10 -2k=2-10....... 2-10= 8. We have to get -2k into just K on itself so we divide by 2. -2k=-8 ______ Your answer is 4. You have to do one side what you do the other. 2
35 + 2k = 9k subtract 2k from each side 35 + 2k - 2k = 9k - 2k 35 = 7k divide both sides integers by 7 35/7 = (7/7)k 5 = k check in original equation 35 + 2(5) = 9(5) 35 + 10 = 45 45 = 45 checks out
It becomes: 2k squared
8k = 6k - 26 8k - 6k = 6k - 6k - 26 2k = -26 2k / 2 = -26 / 2 k = -13. The answer is k = -13.
2k - 1 = 0 Add 1 to both sides: 2k = 1 Divide both sides by two: k = 0.5
Is the following what you are claiming? 2k = 2k+1 -1 20 not equal 20+1 - 1 21 not equal 21+1 -1
2k + 3 = 11(- 3 from both sides)2k = 8(divide both sides by 2)k = 4
k = 14/43
9 - 2k - 3 = k Add 2k to both sides: 9 - 3 = k + 2k Combine like terms: 6 = 3k Divide both sides by 3: 2 = k
neg(-k) + neg(-k) = k + k = 2k = 4
Let even be of the form 2k and odd be of the form 2k+1. Then odd * even becomes 2k*2k+1, or 4k^2 +2k. This can be written as 2(k^2 + k), which is of the form 2k. Therefore, odd X even equals even.
k=4
==> 3k+14=k ==>3k-k=-14 ==>2k=-14 ==>k=-7 ans...
Yes - The expression '2k=6' means six is the result of multiplying k by 2. Therefore k=3, and 6 is (of course) a multiple of 3.
3k-1=k+2 2k=3 k=3/2=1.5