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Write this in the form of single logarithm log x plus log y?
That is the same as log xy.
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
Whats is Log x2 - log xy plus 4 log y?
6
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
Integral of cos2x log cosx-sinx coax plus since?
it is not possible to get the Integral of cos2x log cosx-sinx coax plus since there are no symbols given in the equation.
Rewrite the folling as a logarithmic expression b y equals x?
b y = xlog(b) + log(y) = log(x)
What is 6255 to the power 2 5 to the power of?
6225^2=5^x 38,750,625=5^x log(38,750,625)=xlog(5) log(38,750,625)/log(5)=x x is approximately 10.856
How do you Express 2401 as power of 7?
Set up your equation2401 = 7xNow you have to isolate the x. When can bring down the exponent by taking the Log of both sides.Log(2401) = xLog(7)Now isolate the xx = Log(2401)/Log(7)x = 42401 = 74
The log of the quotient is the log of the numerator plus the log of the denominator?
No. Insert the word "minus" in place of the word "plus", and you'll have a true statement.
What is the expression with the logarithm Log 4 plus Log 3?
log4+log3=log(4x3)=log12
Write this in the form of single logarithm log x plus log y?
That is the same as log xy.
How do you log out of plus network?
you can't
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
What is the value of log5 plus log 5 10 - log 5 4?
1.268293446
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
Could you Condense the expression 5log4 2 plus 7 log4 x plus 4 log 4 y?
You use the identities: log(ab) = b log(a), and log(ab) = log a + log b. In this case, 5 log42 + 7 log4x + 4 log4y = log432 + log4x7 + log4y4 = log4 (32x7y4).
What is log10 plus log33?
One possible answer is log(330) Another is 1 + log(33)
