One possible answer is log(330)
Another is 1 + log(33)
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
pH = -log10[H+] = -log10(0.001 mol/L )= -log10(10-3)= 3
log33+log3x +2=3 log33+log3x=1 log3(3x)=1 3x=3 x=1 Other interpretation: log33+log3(x+2)=3 log3(3(x+2))=3 3(x+2)=27 x+2=9 x=7
logx(3) = log10(7) (assumed the common logarithm (base 10) for "log7") x^(logx(3)) = x^(log10(7)) 3 = x^(log10(7)) log10(3) = log10(x^(log10(7))) log10(3) = log10(7)log10(x) (log10(3)/log10(7)) = log10(x) 10^(log10(3)/log10(7)) = x
The little 'p' means -log10 (that's the negative log to base 10). Thus pH means -log10(Hydrogen ion concentration) → pH of the solution = -log10(7.0 x 10-2) ≈ 1.15
The logarithm base 10 (log10) of 0.00000001 can be calculated as follows: 0.00000001 is equivalent to 10^-8. Therefore, log10(0.00000001) = log10(10^-8) = -8.
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
log5 +log2 =log(5x2)=log(10)=log10(10)=1
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ln(x) = log10(X)/log10(e)
10 log10 (100) or 10 (the exponent of 10 that gives you 100) 10 (2) 20
That goes beyond the capabilities of most scientific calculators, but you can calculate it with logarithms:x = 7^2011 log10(x) = log10(7^2011) log10(x) = 2011 log10(7) x = 10^(2011 log10 7) x = 10^1.699,49 x = 10^0.49 times 10^1699 x = 3.09 times 10^1699