1.268293446
log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1
log5 20 + log5 10 - 3log5 2 = log5 [(20*10)/(2^3)] = log5 25 = 2 (log5 5) = 2
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
The 2nd function of the log button is the inverse log. Press 2nd log, which displays 10^( on the screen. Put a number after the opening parenthesis.
log5 +log2 =log(5x2)=log(10)=log10(10)=1
log5(2) + log5(10) - log5(4) = log5(20/4) = log5(5) = 1
log5 20 + log5 10 - 3log5 2 = log5 [(20*10)/(2^3)] = log5 25 = 2 (log5 5) = 2
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
2logx-log5=-2 logx^2-log5=-2 log(x^2 / 5)=-2 x^2 / 5 = 10^-2 x^2=5(1/100) x^2=1/20 x=√(1/20)
2 log(4y) = log7(343) - log5(25)log7(343) = 3log5(25) = 22 log(4y) = 3 - 2 = 1log(4y) = 0.54y = sqrt(10)y = 0.25 sqrt(10)y = 0.79057 (rounded)
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
The numeric value of log(x) is the power you have to raise 10 to in order to get 'x'.
log (short for logarithm) does not actually have a value. It is actually an operation. So if you see log(10), for instance, you need to take the logarithm of the number in the parenthesis. To do that, just ask yourself "ten raised to WHAT POWER equals the number inside the parenthesis?" And log(#) = that exponent. To finish the example above, log(10) asks you 10? = 10. The answer here is 1, so log(10)=1.
2
Since the pH is defined as the negative log of the H+ concentration, one simply needs to take the negative log of 2.3x10^-9. This value = pH = 8.6
log(9x) + log(x) = 4log(10)log(9) + log(x) + log(x) = 4log(10)2log(x) = 4log(10) - log(9)log(x2) = log(104) - log(9)log(x2) = log(104/9)x2 = 104/9x = 102/3x = 33 and 1/3