n2 - 11n - 26
what two factors of - 26 add up to - 11?
(n + 2)(n - 13)
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n2 + 11n + 18 = n2 + 2n + 9n + 18 = n(n+2) + 9(n+2) = (n+9)*(n+2)
w - 9 is in its simplest form.
64-x2 = (8-x)(8+x) when factored
6(2x - 3y)
(4+x) (2x-3)
You can use the formula for factoring the difference of two squares in this case.
n2 + 11n + 18 = n2 + 2n + 9n + 18 = n(n+2) + 9(n+2) = (n+9)*(n+2)
18 + 8x + x = = 18 + 9x = 9(2 + x) which is the factored form of the expression.
w - 9 is in its simplest form.
64-x2 = (8-x)(8+x) when factored
6(u-14)
6(2x - 3y)
(4+x) (2x-3)
6•2+6•3
"2x(x - 3)"
It's the general form of a quadratic expression and it can be factored providing its discriminant is not less than zero.
D.4(2x - 3)(2x + 1)