D.
4(2x - 3)(2x + 1)
4x times 4x equals 16x2.
factor the trinomial 16x^2+24x+9
4(1 - 4x + 7y)
16x^2 - 25 Recognise that both 16 and 25 are squared numbers, 16 = 4^(2) & 25 = 5^(2) Substituting 4^(2)x^(2) - 5^(2) = > (4x)^(2) - 5^(2) We now have two squared terms with a negative between them. NB two squared terms with positive does NOT factor. Factoring (4x - 5)(4x + 5)
[(-16x)12]1/3 = (-16x)4 = 65536x4
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
4x times 4x equals 16x2.
(4x - 3)(4x - 1)
x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103
To factor the equation ( x^3 + 8x^2 + 16x = 0 ), first, rewrite it as ( x^3 + 8x^2 + 16x + 16 = 16 ). By factoring out the common term ( x ), we get ( x(x^2 + 8x + 16) = 0 ). The quadratic ( x^2 + 8x + 16 ) can be factored as ( (x + 4)^2 ). Therefore, the factored form is ( x(x + 4)^2 = 0 ).
x2+16x-17 = (x-1)(x+17) when factored
x2-16x+48 = (x-4)(x-12) when factored
factor the trinomial 16x^2+24x+9
x5 - 1024 = (x - 4)(x4 + 4x3 + 16x2 + 64x + 256)
16X + 12X all I can see here is factoring out a 4X factor 4X(4 + 3) ---------------
It is: x2-16x+60 = (x-6)(x-10) when factored
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).