36
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
To find the factors of 560 where the middle term is -24, we can express the equation in the form of (x^2 + mx + n = 0), where (m) is the middle term and (n) is the product of the factors. The factors of 560 that also add up to -24 are -14 and -40, since (-14 + (-40) = -24) and (-14 \times -40 = 560). Thus, the required factors are -14 and -40.
t(n) = 6*n where n = 1, 2, 3, etc
It is any number of the form 24*n where n is an integer.
n = 6, 12, 18, 24
6n2
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
24 x 6 = 144 + 8 = 152
24
Depends on the value of n
24 - n = 5n n = 4
$n$ is equal to 140 since 60% of $n$ is equal to 84. To find $n$, you need to divide 84 by 0.6 (or multiply by 100 and then divide by 60). This gives you $n$ = 140.
To find the number of combinations of 5 students that can be chosen from 24 students, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 24 ) and ( k = 5 ), so the calculation is ( C(24, 5) = \frac{24!}{5!(24-5)!} = \frac{24!}{5! \cdot 19!} = \frac{24 \times 23 \times 22 \times 21 \times 20}{5 \times 4 \times 3 \times 2 \times 1} = 42504 ). Therefore, the teacher can choose from 42,504 different combinations of 5 students.
8-n
51. t(n) = (7n4 - 66n3 + 221n2 - 282n + 144)/24 for n = 1,2,3, ..
300
2n = 24 n = 12