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Factor 4n2 plus 28n plus 49?
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
What are the factors for 560 where the middle term is equal to -24?
To find the factors of 560 where the middle term is -24, we can express the equation in the form of (x^2 + mx + n = 0), where (m) is the middle term and (n) is the product of the factors. The factors of 560 that also add up to -24 are -14 and -40, since (-14 + (-40) = -24) and (-14 \times -40 = 560). Thus, the required factors are -14 and -40.
What is the rule for the sequence of 6 12 18 24?
t(n) = 6*n where n = 1, 2, 3, etc
What is the common denominator of 4 3 8?
It is any number of the form 24*n where n is an integer.
The greatest common factor of 30 and a number n is 6 Find a possible value for n Are there other possibilities for n Explain?
n = 6, 12, 18, 24
What does 2 times 3 times n times n equal?
6n2
Factor 4n2 plus 28n plus 49?
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
Evaluate24n k if n 6 andk 8?
24 x 6 = 144 + 8 = 152
What does n equal in the problem n over 3 equals 8?
24
What would n times 5 equal?
Depends on the value of n
How do you write a number subtracted from 24 equals 5 times the number?
24 - n = 5n n = 4
What is the interior angle of an regular decagon?
The interior angle of a regular decagon can be calculated using the formula ((n-2) \times 180^\circ / n), where (n) is the number of sides. For a decagon, (n = 10), so the calculation is ((10-2) \times 180^\circ / 10 = 8 \times 180^\circ / 10 = 144^\circ). Thus, each interior angle of a regular decagon measures 144 degrees.
How many combinations of 5 students can a teacher choose from 24 students?
To find the number of combinations of 5 students that can be chosen from 24 students, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 24 ) and ( k = 5 ), so the calculation is ( C(24, 5) = \frac{24!}{5!(24-5)!} = \frac{24!}{5! \cdot 19!} = \frac{24 \times 23 \times 22 \times 21 \times 20}{5 \times 4 \times 3 \times 2 \times 1} = 42504 ). Therefore, the teacher can choose from 42,504 different combinations of 5 students.
60 of n is 84 what is n?
$n$ is equal to 140 since 60% of $n$ is equal to 84. To find $n$, you need to divide 84 by 0.6 (or multiply by 100 and then divide by 60). This gives you $n$ = 140.
What number comes next in the sequence 1 2 3 5 16?
51. t(n) = (7n4 - 66n3 + 221n2 - 282n + 144)/24 for n = 1,2,3, ..
(-18n2 - 144 n) ÷ (n + 8)?
8-n
How many ways can you choose 3 posters from 24 posters?
To find the number of ways to choose 3 posters from 24, you can use the combination formula, which is given by ( C(n, r) = \frac{n!}{r!(n - r)!} ). Here, ( n = 24 ) and ( r = 3 ). Plugging in the values, we get ( C(24, 3) = \frac{24!}{3!(24 - 3)!} = \frac{24 \times 23 \times 22}{3 \times 2 \times 1} = 2024 ). Thus, there are 2024 ways to choose 3 posters from 24.
