36
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
t(n) = 6*n where n = 1, 2, 3, etc
It is any number of the form 24*n where n is an integer.
n = 6, 12, 18, 24
Yes, every factor pair in an array will have an equal pair, as factors are defined such that when multiplied together, they produce the original number. For example, if ( a ) and ( b ) are factors of a number ( n ), then ( a \times b = n ). In an array, each factor ( a ) will have a corresponding factor ( b ) such that both pairs are equal in their product, ensuring balance within the factor pairs. However, the arrangement of these pairs may differ depending on the context of the array.
6n2
n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).
24
24 x 6 = 144 + 8 = 152
Depends on the value of n
24 - n = 5n n = 4
$n$ is equal to 140 since 60% of $n$ is equal to 84. To find $n$, you need to divide 84 by 0.6 (or multiply by 100 and then divide by 60). This gives you $n$ = 140.
8-n
51. t(n) = (7n4 - 66n3 + 221n2 - 282n + 144)/24 for n = 1,2,3, ..
300
2n = 24 n = 12
50n = 5000 n = 5000/50 n = 100