Oh, dude, alright, so to find natural numbers less than 200 that are divisible by 6 or 9 or both, you just gotta think of multiples of 6 and 9. So, multiples of 6 are like 6, 12, 18, and so on, and multiples of 9 are like 9, 18, 27, and so on. Just list them out and see which ones are less than 200. It's not rocket science, it's just basic math with a sprinkle of laziness.
To find multiples of 7 that are exactly divisible by 3, we need to find numbers that are common multiples of both 7 and 3. The least common multiple of 7 and 3 is 21. Therefore, every multiple of 21 will be exactly divisible by both 7 and 3. Some examples of such numbers include 21, 42, 63, 84, and so on.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
They are both divisible by two.
A Venn diagram for numbers divisible by both 4 and 5 would have two overlapping circles. One circle would represent numbers divisible by 4, while the other circle would represent numbers divisible by 5. The overlapping region where the two circles intersect would represent numbers divisible by both 4 and 5. This intersection would include numbers that are multiples of both 4 and 5, such as 20, 40, 60, and so on.
Multiples of 18.
even numbers are exactly divisible by two. ie. they do not give a remainder when divided by 2. natural numbers are positive integers starting from 1. even natural numbers are a combination of both.. eg. 2,4,50 etc the term positive is not required for these numbers because, natural numbers are positive !... so positive 'natural number' is like saying ' approximated estimate '..
To find multiples of 7 that are exactly divisible by 3, we need to find numbers that are common multiples of both 7 and 3. The least common multiple of 7 and 3 is 21. Therefore, every multiple of 21 will be exactly divisible by both 7 and 3. Some examples of such numbers include 21, 42, 63, 84, and so on.
The set of even natural numbers which are multiples of 3 is an empty set. This is because even numbers are divisible by 2, while multiples of 3 are not divisible by 2. Therefore, there are no numbers that satisfy both conditions simultaneously.
The lists of numbers divisible by and not divisible by 600 are both infinite.
According to a source, there are 44 counting numbers less than 200 that are exactly divisible by either 6 or 9, or by both. To determine the total count, we can follow these steps: Find out how many counting numbers less than 200 are divisible by 6. The last number under 200 that is divisible by 6 is 198, and since 198 is the 33rd multiple of 6, there are 33 such numbers. Next, figure out how many numbers are divisible by 9. The last number under 200 that is divisible by 9 is also 198, and since 198 is the 22nd multiple of 9, there are 22 such numbers. Some numbers will be divisible by both 6 and 9, but we need to avoid counting these twice. So, determine which numbers are divisible by both (these are actually multiples of 18). The last number under 200 that is divisible by 18 is also 198, and since it is the 11th multiple of 18, there are 11 such numbers. Finally, add the two individual counts from steps 1 and 2 together and subtract the count from step 3 to eliminate double counting: 33 + 22 - 11 = 44. Therefore, there are 44 different counting numbers less than 200 that are exactly divisible by either 6 or 9 or both.
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
972 is one of the numbers that is divisible by both.
No, they are both even and odd. The numbers 18 and 36 are examples of even numbers divisible by nine.
It doesn't have a numerical answer. If both numbers are even, one will be divisible by the other.
How many numbers less than 700 are divisible by both 15 and 21?
Yes.
Numbers up to 200 divisible by both 2 and 3 = numbers to 200 divisible by 2*3 = 6 which is int(200/6) = int(33.33) = 33