To find numbers that multiply to give you 231, you can factorize 231 and look for its prime factors.
231 = 3 * 7 * 11
So, the numbers you can multiply to get 231 are 3, 7, and 11.
As a product of its prime numbers: 3*7*11 = 231
3 x 77
The three prime numbers which multiply to make 231 are 3 x 7 x 11.
The prime factorization of 231 = 3 x 7 x 11
231 = 3 x 7 x 11
3, 7 and 11
Just multiply the two numbers to get it (which is, by the way,231)
There are only 3 of them because as a product if its prime factors: 3*7*11 = 231
693
1 x 231, 3 x 77, 21 x 11, 33 x 7. Add the digits and you get 6, which means it is divisible by 3. (3 x 77) 77 has two prime factors, 7 and 11. So you can multiply any combination of the factors to get 231. 3C2 (3 choose 2) in Pascal's triangle is 3, which means there are three possible combinations. Oh, yeah, and you can always just do 1 x 231.
(-77,3)(-33,7)(-21,11)(77,-3)(33,-7)(21,-11)
-231. To get the opposite of a number, multiply it by -1.