3 x 7 x 11 = 231
To determine factors of a number it is necessary to divide the number by prime numbers of increasing value. If there is no remainder then the prime number is a factor. The square root of 231 is approximately 15 so it is necessary to divide by all the prime numbers up to 13 (15 is not a prime number). 231 ÷ 2 leaves a remainder of 1 231 ÷ 3 divides exactly 77 times (which is 7 x 11 - both are prime numbers) 231 ÷ 5 leaves a remainder of 1 231 ÷ 7 divides exactly 33 times (which is 3 x 11 - both are prime numbers) 231 ÷ 11 divides exactly 21 times (which is 3 x 7 - both are prime numbers) 231 ÷ 13 leaves a remainder of 10 If we multiply together the three numbers that are shown to be factors 3 x 7 x 11 = 231 this confirms that there are no other factors of 231 except 1 and 231 itself. This last condition is true for every positive integer. 231 is divisible by 1, 3, 7, 11 and 231
1 x 231, 3 x 77, 21 x 11, 33 x 7. Add the digits and you get 6, which means it is divisible by 3. (3 x 77) 77 has two prime factors, 7 and 11. So you can multiply any combination of the factors to get 231. 3C2 (3 choose 2) in Pascal's triangle is 3, which means there are three possible combinations. Oh, yeah, and you can always just do 1 x 231.
Calculator says search a prime factor calculator, its, from my head, 3*7*11
76 + 77 + 78 three numbers in a row
The prime factorization of 231 = 3 x 7 x 11
The three prime numbers which multiply to make 231 are 3 x 7 x 11.
To find numbers that multiply to give you 231, you can factorize 231 and look for its prime factors. 231 = 3 * 7 * 11 So, the numbers you can multiply to get 231 are 3, 7, and 11.
As a product of its prime numbers: 3*7*11 = 231
231 = 3 x 7 x 11
There are only 3 of them because as a product if its prime factors: 3*7*11 = 231
3, 7 and 11
They are: 2+229 = 231
The prime factorization of 231 = 3 x 7 x 11
The prime factorization of 231 is 3 x 7 x 11.
They are: 3*7*11 = 231
3 x 7 x 11 = 231