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1 x 231, 3 x 77, 21 x 11, 33 x 7.

Add the digits and you get 6, which means it is divisible by 3. (3 x 77) 77 has two prime factors, 7 and 11. So you can multiply any combination of the factors to get 231. 3C2 (3 choose 2) in Pascal's triangle is 3, which means there are three possible combinations. Oh, yeah, and you can always just do 1 x 231.

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19×13=

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When you multiply two numbers, you get the product

693

When you multiply two numbers, it is called the product.

The two (or more) numbers that you multiply are called factors. (The result of the multiplication is called the product.)

Two numbers that you can multiply together to get 72 are: 36 and 2.

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To find numbers that multiply to give you 231, you can factorize 231 and look for its prime factors. 231 = 3 * 7 * 11 So, the numbers you can multiply to get 231 are 3, 7, and 11.

3 x 77

Just multiply the two numbers to get it (which is, by the way,231)

As a product of its prime numbers: 3*7*11 = 231

(-77,3)(-33,7)(-21,11)(77,-3)(33,-7)(21,-11)

The three prime numbers which multiply to make 231 are 3 x 7 x 11.

The prime factorization of 231 = 3 x 7 x 11

231 = 3 x 7 x 11

3, 7 and 11

There are only 3 of them because as a product if its prime factors: 3*7*11 = 231

When you multiply two numbers, you get the product

693