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1 x 231, 3 x 77, 21 x 11, 33 x 7.

Add the digits and you get 6, which means it is divisible by 3. (3 x 77) 77 has two prime factors, 7 and 11. So you can multiply any combination of the factors to get 231. 3C2 (3 choose 2) in Pascal's triangle is 3, which means there are three possible combinations. Oh, yeah, and you can always just do 1 x 231.

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12y ago
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Anonymous

Lvl 1
4y ago

19×13=

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Numbers which I can multiply to get 231 as my answer?

To find numbers that multiply to give you 231, you can factorize 231 and look for its prime factors. 231 = 3 * 7 * 11 So, the numbers you can multiply to get 231 are 3, 7, and 11.


What two numbers can you multiply to get 231?

3 x 77


What are multiples of 9 and 24?

Just multiply the two numbers to get it (which is, by the way,231)


How do you work out the three prime numbers to multiply which makes 231?

As a product of its prime numbers: 3*7*11 = 231


What two numbers multiply to equal -231?

(-77,3)(-33,7)(-21,11)(77,-3)(33,-7)(21,-11)


What three prime numbers which multiply to make231?

The three prime numbers which multiply to make 231 are 3 x 7 x 11.


What three prime numbers multiply to make 231?

The prime factorization of 231 = 3 x 7 x 11


Write the three prime numbers which multiply to make 231?

231 = 3 x 7 x 11


What 3 prime numbers multiply up to 231?

3, 7 and 11


4 prime numbers that multiply to 231?

There are only 3 of them because as a product if its prime factors: 3*7*11 = 231


When you multiply two numbers what do you get?

When you multiply two numbers, you get the product


What 3 prime numbers multiply to make 231?

693