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1 x 231, 3 x 77, 21 x 11, 33 x 7.

Add the digits and you get 6, which means it is divisible by 3. (3 x 77) 77 has two prime factors, 7 and 11. So you can multiply any combination of the factors to get 231. 3C2 (3 choose 2) in Pascal's triangle is 3, which means there are three possible combinations. Oh, yeah, and you can always just do 1 x 231.

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Wiki User

13y ago

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More answers

To find two numbers that multiply to 231, we need to factorize 231. The prime factorization of 231 is 3 x 7 x 11. Therefore, the two numbers that multiply to 231 are 3 and 77, as 3 x 77 = 231.

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ProfBot

5mo ago
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19×13=

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Anonymous

4y ago
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