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PH equals -logH3O plus

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Anonymous

15y ago
Updated: 8/18/2019

true

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15y ago

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How many moles of H3O are present in an 85 L solution with a pH of 3.0?

To find the number of moles of H3O in the solution, you can use the formula pH -logH3O. First, calculate the concentration of H3O ions using the pH value: pH -logH3O 3.0 -logH3O H3O 10(-3.0) 1.0 x 10(-3) M Next, calculate the number of moles of H3O in the solution using the concentration and volume: moles concentration x volume moles 1.0 x 10(-3) mol/L x 85 L moles 8.5 x 10(-2) moles Therefore, there are 8.5 x 10(-2) moles of H3O present in the 85 L solution with a pH of 3.0.


True or false pH equals -log H3O plus?

True


What is the pH when the H plus equals 10-7 M?

3


What is the pH of a solution with a H plus equals 10 -8?

2


What is the pH of a solution with H plus equals 9.40 x 10-4?

-log(9.40 X 10^-4) = 3 pH


What is the pH of a solution in which H3O plus equals 4.1 x 10-2 M?

1.39


Which of these solutions are acidic a solution with OH equals 2.5 10-9 H plus equals 1.2 10 -4 H plus equals 3.4 10-8 pH equals 4.5 OH equals 1.0 10-4?

solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5


How to Evaluate the ratio MH plus pH 3 divided by MH plus pH 7?

To evaluate the ratio MH plus pH 3 divided by MH plus pH 7, first determine the molar concentration of each species at pH 3 and pH 7 using the Henderson-Hasselbalch equation. Then calculate the ratio of the concentrations of MH at pH 3 to pH 7, and divide this by the ratio of pH 3 to pH 7.


What is the pH for a solution that has h plus equals 3.6 x 10 -9 M?

pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4


A solution of HCl has H plus equals 5.5 x 10-4 What is the pH of this solution?

apexvs answer 3.3


What is the pH of a solution with H plus equals 7.0 10 2?

The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.


What is the pH of a solution with an H plus equals 1.2 x 10-5?

-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)