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C being 100, X being ten, and L being fifty, the way to do this is as follows:

100:___::10:50

100x5=______, because 10x5=50

100:100x5::10:50

100:500::10:50

Convert to roman numerals, and you get:

C:D::X:L

Or C is to D, as X is to L.

Q: Please solve C is to as x is to l?

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19 = XIX 49 = XLIX 99 = XCIX Expected result is 167 = CLXVII Method 1: Convert subtractive pairs so IV becomes IIII, XL becomes XXXX and XC becomes LXXXX. Then sort values in descending order of value, grouping C, X and I in groups of 5, and L and V in groups of 2, then reduce these groups so that IIIII becomes V, VV becomes X, XXXXX becomes L and LL becomes C. XIX + XLIX + XCIX = XVIIII + XXXXVIIII + LXXXXVIIII = L + XXXXX + XXXX + VV + V + IIIII + IIIII + II = L + XXXXX + XXXX + VV + VV + V + II = L + XXXXX + XXXXX + X + V + II = LL + L + X + V + II = C + L + X + V + II = CLXVII Method 2: Expand all symbols into positive and negative symbols, sort by absolute value, cancel out any similar values with opposing signs. Convert higher values to lower values as required. XIX + XLIX + XCIX = X - I + X - X + L - I + X - X + C - I + X = C + L + X + X - X + X - X + X - I - I - I = C + L + X + X - I - I - I = C + L + X + V + V - I - I - I = C + L + X + V + I + I + I + I + I - I - I - I = C + L + X + V + I + I = CLXVII

560

C x v lit's one hundred sixteen

M c m l x x x i i

W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42