H = A/(L x W)
135 = c x x x v120 = c x x200 = c c70 = L x x190 = c x c65 = L x v
ax - b = c ax = b + c x = (b + c)/a
1/x=c+1/b, solve for x x=c+b/1
D c c l x x i
1872 = MDCCCLXXII
ax - x = c therefore x*(a - 1) = c Provide a ≠1, divide both sides by a - 1 to give x = c/(a - 1) If a = 1 then the value of x is indeterminate.
19 = XIX 49 = XLIX 99 = XCIX Expected result is 167 = CLXVII Method 1: Convert subtractive pairs so IV becomes IIII, XL becomes XXXX and XC becomes LXXXX. Then sort values in descending order of value, grouping C, X and I in groups of 5, and L and V in groups of 2, then reduce these groups so that IIIII becomes V, VV becomes X, XXXXX becomes L and LL becomes C. XIX + XLIX + XCIX = XVIIII + XXXXVIIII + LXXXXVIIII = L + XXXXX + XXXX + VV + V + IIIII + IIIII + II = L + XXXXX + XXXX + VV + VV + V + II = L + XXXXX + XXXXX + X + V + II = LL + L + X + V + II = C + L + X + V + II = CLXVII Method 2: Expand all symbols into positive and negative symbols, sort by absolute value, cancel out any similar values with opposing signs. Convert higher values to lower values as required. XIX + XLIX + XCIX = X - I + X - X + L - I + X - X + C - I + X = C + L + X + X - X + X - X + X - I - I - I = C + L + X + X - I - I - I = C + L + X + V + V - I - I - I = C + L + X + V + I + I + I + I + I - I - I - I = C + L + X + V + I + I = CLXVII
560
C x v lit's one hundred sixteen
M c m l x x x i i
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42