4 x 4 = 16.
If you multiply the last digit by 4: 6 x 4 = 24 (ends with 4).
Continue multiplying by 4, and you see that the last digit will always alternate between 4 and 6 - 4 for the odd powers, and 6 for the even powers.
So, in this case, the answer is 4.
The prime number between 20 and 30 whose ones digit is 7 greater than its tens digit is 23. The tens digit is 2, and the ones digit is 3, which is 7 greater than 2. Additionally, 23 is a prime number because it is only divisible by 1 and itself, with no other factors.
29 is not divisible by 3 and how any digit will alter that depends on how that digit is to interact with 29.
To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is (9). Thus, the units digit of (29^{57}) is (9).
Well, isn't that a happy little number! If we're rounding 28.67 to the nearest whole number, we see that the decimal part is less than 0.5, so it will round down to 29. Just a little adjustment to keep things nice and tidy!
To find the units digit of (29^{57}), we can focus on the units digit of the base, which is 9. The units digits of the powers of 9 follow a pattern: (9^1 = 9), (9^2 = 81) (units digit 1), (9^3 = 729) (units digit 9), and (9^4 = 6561) (units digit 1). This pattern alternates between 9 and 1. Since (57) is odd, the units digit of (29^{57}) is the same as that of (9^{57}), which is 9.
No, a number with a 9 in the ones place is not always divisible by 3. For a number to be divisible by 3, the sum of its digits must be divisible by 3, regardless of the digit in the ones place. For example, the number 29 has a 9 in the ones place, but its digit sum (2 + 9 = 11) is not divisible by 3.
Well, Garth needs to multiply the ones digit of 29 by the ones digit of 16 to get 174, which is correct. Then, he needs to multiply the tens digit of 29 by the ones digit of 16 to get 290, which is also correct. To find the final product, Garth should add these two results together, giving him a total of 464. Easy peasy lemon squeezy!
the digit 2 is in the ten's place.
23 and 29
It is a 29-digit integer. So what?
The nearest ten of 29 is 30. When determining the nearest ten of a number, you look at the digit in the ones place. If the digit is 5 or greater, you round up to the next ten; if it is less than 5, you round down to the current ten. In this case, the digit in the ones place of 29 is 9, which is greater than 5, so we round up to 30.
12 x 12 = 144 21 x 21 = 441 29 x 29 = 841 As you may have noticed, all these 3 digit square numbers have a 4 as the second digit. Hope this helped