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Probability of dealing ace king and queen of spades in that order when dealing only 3 cards?
Wiki User
∙ 14y ago
The probability of dealing the Ace of Spades from a normal 52 card deck is 1 in 52. The probability of dealing the King of Spades next is 1 in 51. The probability of dealing the Queen of Spades next is 1 in 50.
The probability of drawing those three cards in that order is the product of those probabilities, which is 1 in 132,600. This is the same as the number of permutations of N (52) things taken P (3) at a time, which is stated as N! - P! (52 * 51 * 50)
If you did not care what order the cards were dealt in, but still wanted to know the probability of getting the Ace, King, and Queen of Spades, then you would be talking about the combinations of N (52) things taken P (3) at a time, which is stated as (N! - P!) / (N - P)! (52 * 51 * 50 / 3 / 2 / 1). The probability in this case is 1 in 22,100.
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∙ 14y ago
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What is the probability of dealing an ace king and queen in that order when dealing only three cards?
Assuming you mean from a standard 52-card deck of four suits, there is a 4/52 chance of first dealing an ace, a 4/51 chance of secondly dealing a king and a 4/50 chance of dealing a queen. Together, these mean there is a 64/132600, or 8/16575 or 0.04826546% chance of dealing the desired cards in order.
What is the probability of the next card is higher if the card is 7 in 13 cards in an order?
It is 1/2 and depends on whether the cards are in ascending or descending order.
How do you calculate propability of a deck of cards?
The probability is the likely outcome of a random event. In this example - picking (say) the Ace of Spades - the chances are 1 in 52. Drawing a red card is 1 in 2, drawing a Spade is 1 in 13 etc. The probability of drawing every card in order from a pre-written list is approximately 1 in 8 x 1067 !
5 cards r numbered with a different integer 1 to 5 the Cards r then shuffled so they are not in order If 2 cards r selected at random without replacement what is the probability that the sum is 8?
1/10 or 10%
Two cards are drawn at random form a starnard deck of 52 cards without replacement what is the propertility of drawing a 7 and a king in that order?
You mean the PROBABILITY? It's 13/52*13/51 = 13/204
What is the probability of dealing an ace king and queen in that order when dealing only three cards?
Assuming you mean from a standard 52-card deck of four suits, there is a 4/52 chance of first dealing an ace, a 4/51 chance of secondly dealing a king and a 4/50 chance of dealing a queen. Together, these mean there is a 64/132600, or 8/16575 or 0.04826546% chance of dealing the desired cards in order.
What is the probability of drawing an ace of spades and a heart from a deck of cards in two successive draws without placing the first card back in the deck of 52?
There's only one Ace of spades in a 52 card deck so it's 1/52 times the probability of drawing a heart (there are 13 hearts in the same deck, but now there are 51 cards because we already drew one out). That makes it 1/52 * 13/51 = 13/2652 = 1/204 This is if you want the Ace first, then the heart, if order doesn't matter, you add this to the probability of drawing the heart first, then the Ace of Spades which is (13/52*1/51) =1/204 notice is the same as the first one. So if order doesn't matter, the probability is 1/204 + 1/204 = 2/204 = 1/102
What is the probability of drawing 1 card from each suit if 4 cards are drawn from a deck?
The easiest way to do this is to first calculate the probability of drawing spade/heart/club/diamond in order. This is 13/52 times 13/51 time 13/50 times 13/49. Note that each time there are 13 possible cards to choose from out of a shrinking deck. This probability comes out at 0.004396. The reason it's so small is that we haven't accounted for all the different ways you can draw the cards. You might draw the spades first, or the hearts first. There are 4x3x2x1 different orders the cards can come in. Multiply the probability by this and you get 0.1055 So the probability of having 1 card from each suit is 0.1055
In a deck of playing cards why is the king of spades the only king with it's head turned to the right?
Arange the 4 kings in this order spades grapes. Hearts and diamonds, the king of diamonds is about to get killed and the king of spades is the only one that notices the murder
What is the probability of the next card is higher if the card is 7 in 13 cards in an order?
It is 1/2 and depends on whether the cards are in ascending or descending order.
How do you eat a pack of cards?
First you start with the ace of hearts then in order. Go in order abd do the same to the diamonds, clubs, and spades. I found it easier that way.
How do you calculate propability of a deck of cards?
The probability is the likely outcome of a random event. In this example - picking (say) the Ace of Spades - the chances are 1 in 52. Drawing a red card is 1 in 2, drawing a Spade is 1 in 13 etc. The probability of drawing every card in order from a pre-written list is approximately 1 in 8 x 1067 !
What is the probability of drawing 2 hearts and then a spade in that order from a deck of 52 cards?
In order to determine the probability of drawing 2 hearts and then a spade, in that order, from a deck of 52 cards, start by considering the first card. The probability of drawing a heart is 1 in 4. Since you have now reduced the number of hearts and the number of cards in the deck by one, the probability of drawing another heart is 4 in 17. Since you have further reduced the number of cards by one, the probability of drawing a spade is 13 in 50. Multiply these probabilities together, (1/4) (4/17) (13/50), and you get about 0.0153, or about 153 in 10000.
If 2 cards are selected from a standard deck of 52 cards without replacement find the probability that both are the same suit?
If 2 cards are selected from a standard deck of 52 cards without replacement, in order to find the probability that both are the same suit, start with the first card...The probability that the first card is any suit is 52 in 52, or 1.Now, consider the second card. There are 12 cards remaining in the same suit, and 39 cards remaining in the other three suits...The probability that the second card is the same suit as the first card is 12 in 51, or 4 in 17, or 0.235.The probability of both events occurring is the product of those two probabilities. That is still 4 in 17, or 0.235.
Why is the Ace of Spades the most popular card in a deck of playing cards?
In colonial America the Ace of spades was where they placed the British tax stamp. __________________ It is also the card that shows when they package decks of cards, so they usually glam it up a little, and that is usually where you can find manufacturer information. In card games that recognize suit superiority, Spades is the highest suit, and the Ace the most powerful card, so it is representative of the "ultimate" card in some ways.
5 cards r numbered with a different integer 1 to 5 the Cards r then shuffled so they are not in order If 2 cards r selected at random without replacement what is the probability that the sum is 8?
1/10 or 10%
What is the probability of drawing a spade and a diamond in any order?
Assume that you start with a well-shuffled regular 52-card deck (no jokers) and draw 2 cards. The first card can be either a spade or a diamond, giving you 26 possibilities out of the 52 cards, for a probability of 26/52 or 1/2. The second card must be of the other desired suit, giving you 13 possibilities out of the 51 remaining cards, for a probability of 13/51. The total probability is then the product of the two, 1/2 x 13/51 = 13/102, or about 12.74%.
