1/5
Let n be the number, then: 1/n - 1/3n = 1/6 Solve the subtraction on the left: 1/n - 1/3n = 3/3n - 1/3n = 2/3n But we know this is 1/6, thus: 2/3n = 1/6 ⇒ 3n = 12 ⇒ n = 4 Thus the number is 4.
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n -5 = 19 3n = 19+5 3n = 24 n = 8
3n(n+1] + 5 is the nth term
3n - 2n = n 3n - 2n = (3 - 2)n = 1n = n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
3n and n = 4? 3n ( the four replaces the n 3(4) = 12 =======
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
what is 3n times 3n-1
3n - 24 = 14 - 30n33n = 38n = 38/33
3n-5=13 +5 +5 3n=18 /3 /3 n=6