if this is x squared -6x+6=0
-6=b, a=1, c=6
6+ square root of -6 squared-4(6x1)
6+ square root of (36-24)
6+ square root of 12
6+ square root of 4 x square root of 3
6 + (2x square root of 3)
that is all divided by 2 multiplied by a
meaning it is divided by 2.
so x= 6 + or - (2 square root 3)
divided by 2
srry steps are jmbled
By using the quadratic equation formula
With great difficulty because it is not a quadratic equation or even a quadratic expression.
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
You can't because it is not a quadratic equation.
By using the quadratic equation formula or by completing the square
Yes. You can calculate the two roots of a quadratic equation by using the quadratic formula, and because there are square roots on the quadratic formula, and if the radicand is not a perfect square, so the answer to that equation has decimal.
Using the quadratic equation formula is a method of solving quadratic equations.
You can solve a quadratic equation 4 different ways. graphing, which is quick but not reliable, factoring, completing the square and using the quadratic formula. There is a new fifth method, called Diagonal Sum Method, that can quickly and directly give the 2 roots in the form of 2 fractions, without having to factor the equation. It is fast, convenient, and is applicable whenever the equation can be factored. Finally, you can proceed solving in 2 steps any given quadratic equation in standard form. If a=1, solving the equation is much simpler. First, you always solve the equation in standard form by using the Diagonal Sum Method. If it fails to find answer, then you can positively conclude that the equation is not factorable, and consequently, the quadratic formula must be used. In the second step, solve the equation by using the quadratic formula.
By using the quadratic formula. (-b±√b2-4ac)/(2a)
Using the quadratic formula to solve any quadratic equation is the best way of getting around it because the quadratic formula is "the opposite of b plus or minus the square root of b squared minus 4ac all divided by 2a. This formula only works with trinomials and second degree equaitons. If the equation is a binomial, then put in a placeholer (0) and substitute them into the equation.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
Using the quadratic equation formula: x = 8.42 or x = -1.42
X= (3/5 , -2)
It can be solved by using the quadratic equation formula.
There are different methods of using quadratic functions depending on the equation.
Well, if the given quadratic equation cannot be factored, nor completed by the square, try using the quadratic formula.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
s^2 +4x -21 = 0 is a quadratic equation and by using the quadratic equation formula its solutions are s = 3 or s = -7
Using the quadratic equation formula or completing the square
By using the quadratic equation formula: x = -5 and x = 3
The answer of the equation 2a -46a plus 252 = 0 using the quadratic formula is a = 5.25.
Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign If so then by using the quadratic equation formula the values of y both equal 4