Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
Using the quadratic equation formula:- x = -3 + sq rt of 22 and x = -3 - sq rt of 22
-22
22 x 0.35 = 7.7
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
11 and 11. In general, you can write an equation (or two equations), and solve with the quadratic formula, to solve this type of questions.
Using the quadratic equation formula:- x = -3 + sq rt of 22 and x = -3 - sq rt of 22
-22
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
This requires solving a quadratic. Let one number be x The other number is (10-x) Their product is: x(10-x) = 22 10x - x² = 22 x² -10x + 22 = 0 Now apply the quadratic formula: b² - 4ac = 100 - 88 = 12 x = (10 ± √12)/2 since √12 = 2√3 x = 5 ±√3 So the two numbers are: 5+√3 and 5-√3 Sum is 10 (check) Product is 25-3 = 22 (check)
I think it is written wrong, try again
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
-129 + 22 = -107
It is a linear equation in the variable x. You can solve for x using algebra: -5x + 3 = -22 -5x = -25 -x = -5 x = 5
Lets say that the equation is: 2+3x+2x=222+5x=22 Combine Like Terms.2-2+5x=22-2 Subtract 2 from each side.5x=20 Simplify.5x/5=20/5 Divide 5 on each side.x=4 Simplify.Check...2+3x+2x=22 x=42+3(4)+2(4)=22 Substitute x for 4.2+12+8=22 Multiply and Divide first from left to right.14+8=22 Add and Subtract from left to right.22=22Should you have an equation with higher order (like x2) then different methods, like factoring or the quadratic formula will apply.Eh?