if this is x squared -6x+6=0
then
-6=b, a=1, c=6
6+ square root of -6 squared-4(6x1)
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6+ square root of (36-24)
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6+ square root of 12
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6+ square root of 4 x square root of 3
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6 + (2x square root of 3)
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that is all divided by 2 multiplied by a
meaning it is divided by 2.
so x= 6 + or - (2 square root 3)
divided by 2
srry steps are jmbled
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By using the quadratic equation formula
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
With great difficulty because it is not a quadratic equation or even a quadratic expression.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
You can't because it is not a quadratic equation.
By using the quadratic equation formula or by completing the square
By using the quadratic formula. (-b±√b2-4ac)/(2a)
You can solve a quadratic equation 4 different ways. graphing, which is quick but not reliable, factoring, completing the square and using the quadratic formula. There is a new fifth method, called Diagonal Sum Method, that can quickly and directly give the 2 roots in the form of 2 fractions, without having to factor the equation. It is fast, convenient, and is applicable whenever the equation can be factored. Finally, you can proceed solving in 2 steps any given quadratic equation in standard form. If a=1, solving the equation is much simpler. First, you always solve the equation in standard form by using the Diagonal Sum Method. If it fails to find answer, then you can positively conclude that the equation is not factorable, and consequently, the quadratic formula must be used. In the second step, solve the equation by using the quadratic formula.
Using the quadratic equation formula is a method of solving quadratic equations.
Yes. You can calculate the two roots of a quadratic equation by using the quadratic formula, and because there are square roots on the quadratic formula, and if the radicand is not a perfect square, so the answer to that equation has decimal.
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2