if this is x squared -6x+6=0
then
-6=b, a=1, c=6
6+ square root of -6 squared-4(6x1)
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6+ square root of (36-24)
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6+ square root of 12
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6+ square root of 4 x square root of 3
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6 + (2x square root of 3)
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that is all divided by 2 multiplied by a
meaning it is divided by 2.
so x= 6 + or - (2 square root 3)
divided by 2
srry steps are jmbled
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3x2+x-4 = 0 (3x+4)(x-1) = 0 Solutions: x = 1 and x = -4/3 By using the quadratic equation formula.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
To find the points of intersection on the x-axis, set y equal to zero and solve for x. So, 8x^2 - 26x + 15 = 0. This is a quadratic equation that can be factored or solved using the quadratic formula. Once you find the values of x, those are the points of intersection on the x-axis.
It is not to solve so much as to see the number of solutions and whether there is a real solution to the equation. b2 - 4(a)(c) A positive answer = two real solutions. A negative answer = no real solution ( complex solution i ) If zero as the answer there is one real solution.
x = 9/2 or x = -2 Solved by using the quadratic equation formula.
By using the quadratic equation formula
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
With great difficulty because it is not a quadratic equation or even a quadratic expression.
You can't because it is not a quadratic equation.
A quadratic equation normally has 2 solutions and can be solved by using the quadratic equation formula.
By using the quadratic equation formula or by completing the square
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
Yes. You can calculate the two roots of a quadratic equation by using the quadratic formula, and because there are square roots on the quadratic formula, and if the radicand is not a perfect square, so the answer to that equation has decimal.
Using the quadratic formula to solve any quadratic equation is the best way of getting around it because the quadratic formula is "the opposite of b plus or minus the square root of b squared minus 4ac all divided by 2a. This formula only works with trinomials and second degree equaitons. If the equation is a binomial, then put in a placeholer (0) and substitute them into the equation.
Using the quadratic equation formula: x = 8.42 or x = -1.42
X= (3/5 , -2)